10x^2=600

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Solution for 10x^2=600 equation:



10x^2=600
We move all terms to the left:
10x^2-(600)=0
a = 10; b = 0; c = -600;
Δ = b2-4ac
Δ = 02-4·10·(-600)
Δ = 24000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{24000}=\sqrt{1600*15}=\sqrt{1600}*\sqrt{15}=40\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{15}}{2*10}=\frac{0-40\sqrt{15}}{20} =-\frac{40\sqrt{15}}{20} =-2\sqrt{15} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{15}}{2*10}=\frac{0+40\sqrt{15}}{20} =\frac{40\sqrt{15}}{20} =2\sqrt{15} $

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